Sponsored Links


Results 1 to 3 of 3

Thread: CS601-Data Communication Solution of Assignment No. 02 November Fall 2013

  1. #1
    Senior Member
    Join Date
    Oct 2012
    Posts
    323

    CS601-Data Communication Solution of Assignment No. 02 November Fall 2013

    Sponsored Links


    Assignment No. 02
    Semester: Fall 2013
    CS601-Data Communication


    Total Marks: 20
    Due Date: 6/12/2013




    Question 1: (10 Marks)

    You are required to represent the data stream 1001101001 using the following encoding schemes on different graphs separately.

    NRZ-L
    NRZ-I

    Question 2: (5 Marks)

    a) A periodic signal has a bandwidth of 700 Hz and its lowest frequency is 200 Hz; find out its highest frequency with all necessary steps.

    b) Consider the following sine wave, and calculate its time period and frequency.

    Name:  cs601.jpg
Views: 2362
Size:  36.8 KB


    Question 3: (5 Marks)

    Suppose a message travels from device A to B in OSI model. Headers and trailers are added to the message before it reaches the destination B. Considering the given scenario, you are required to identify:
    The sequence of OSI layers in which headers and trailers are added at device A.
    The sequence of OSI layers in which headers and trailers are removed at device B.

  2. #2
    Senior Member
    Join Date
    Oct 2012
    Posts
    323
    What is the major difference between NRZ-L and NRZI?

    "Non return-to-zero-level (NRZ-L) is a data encoding scheme in which a negative voltage is used to represent binary one and a positive voltage is used to represent binary zero. As with NRZ-L, NRZI maintains a constant voltage pulse for the duration of a bit time. The data themselves are encoded as the presence or absence of a signal transition at the beginning of the bit time. A transition (low to high or high to low) at the beginning of a bit time denotes a binary 1 for that bit time; no transition indicates a binary 0."

    The frequency of a wave is the amount of time the wave goes through a complete cycle in a second. The unit of frequency is Hertz, which literally means "per second". So if the frequency of a wave is 30 Hz, the wave goes through 30 complete cycles in one second.
    The simplest way to calculate frequency using time would be to count the amount of complete cycles that the wave goes through in a second. Or, if it would be easier, you could count the amount of cycles in a minute and divide by 60 (or hour and divide by 3600, etc.)

  3. #3
    Senior Member
    Join Date
    Oct 2012
    Posts
    323
    Name:  1.1.jpg
Views: 2373
Size:  7.0 KB

    Name:  2.2.jpg
Views: 2375
Size:  8.3 KB

    Name:  3.3.jpg
Views: 2408
Size:  54.2 KB

    Name:  4.4.jpg
Views: 2399
Size:  37.6 KB

    Name:  5.5.jpg
Views: 2345
Size:  9.7 KB

    Best of Luck...

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Similar Threads

  1. Replies: 0
    Last Post: 01-23-2013, 11:07 AM
  2. CS601 Data Communication Assignment No 1 Solution Fall 1st November 2012
    By vuassignments in forum Assignments & Solutions
    Replies: 0
    Last Post: 11-01-2012, 03:48 PM
  3. CS601- Data Communication Assignment 2 Solution required
    By marshadm85 in forum Get Solution In 24 Hour
    Replies: 4
    Last Post: 11-15-2011, 03:26 PM
  4. Replies: 1
    Last Post: 11-11-2011, 12:35 AM
  5. Replies: 1
    Last Post: 01-27-2011, 02:37 PM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  
-: Vuhelp Disclaimer :-
None of the files shown here are hosted or transmitted by this server. The links are provided solely by this site's users. The administrator's or staff of Vuhelp.net cannot be held responsible for what its users post, or any other actions of its users. You may not use this site to distribute or download any material when you do not have the legal rights to do so. It is your own responsibility to adhere to these terms. If you have any doubts about legality of content or you have any suspicions, feel free to contact us.
Online Education